3x=(1/9)^2x-10

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Solution for 3x=(1/9)^2x-10 equation: 



3x=(1/9)^2x-10

We move all terms to the left:

3x-((1/9)^2x-10)=0



Domain of the equation: 9)^2x-10)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3x-((+1/9)^2x-10)=0

We multiply all the terms by the denominator


3x*9)^2x-10)-((+1=0

Wy multiply elements

27x^2+1=0

a = 27; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·27·1
Δ = -108
Delta is less than zero, so there is no solution for the equation

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